JavaScript MCQ Practice Part 6
126. What's the output?
function getFine(speed, amount) {
const formattedSpeed = new Intl.NumberFormat({
'en-US',
{ style: 'unit', unit: 'mile-per-hour' }
}).format(speed)
const formattedAmount = new Intl.NumberFormat({
'en-US',
{ style: 'currency', currency: 'USD' }
}).format(amount)
return `The driver drove ${formattedSpeed} and has to pay ${formattedAmount}`
}
console.log(getFine(130, 300))
- A: The driver drove 130 and has to pay 300
- B: The driver drove 130 mph and has to pay $300.00
- C: The driver drove undefined and has to pay undefined
- D: The driver drove 130.00 and has to pay 300.00
Answer
Answer: B
With the Intl.NumberFormat
method, we can format numeric values to any locale. We format the numeric value 130
to the en-US
locale as a unit
in mile-per-hour
, which results in 130 mph
. The numeric value 300
to the en-US
locale as a currentcy
in USD
results in $300.00
.
127. What's the output?
const spookyItems = ['π»', 'π', 'πΈ'];
({ item: spookyItems[3] } = { item: 'π' });
console.log(spookyItems);
- A:
["π»", "π", "πΈ"]
- B:
["π»", "π", "πΈ", "π"]
- C:
["π»", "π", "πΈ", { item: "π" }]
- D:
["π»", "π", "πΈ", "[object Object]"]
Answer
Answer: B
By destructuring objects, we can unpack values from the right-hand object, and assign the unpacked value to the value of the same property name on the left-hand object. In this case, we're assigning the value "π" to spookyItems[3]
. This means that we're modifying the spookyItems
array, we're adding the "π" to it. When logging spookyItems
, ["π»", "π", "πΈ", "π"]
gets logged.
128. What's the output?
const name = 'Lydia Hallie';
const age = 21;
console.log(Number.isNaN(name));
console.log(Number.isNaN(age));
console.log(isNaN(name));
console.log(isNaN(age));
- A:
true
false
true
false
- B:
true
false
false
false
- C:
false
false
true
false
- D:
false
true
false
true
Answer
Answer: C
With the Number.isNaN
method, you can check if the value you pass is a numeric value and equal to NaN
. name
is not a numeric value, so Number.isNaN(name)
returns false
. age
is a numeric value, but is not equal to NaN
, so Number.isNaN(age)
returns false
.
With the isNaN
method, you can check if the value you pass is not a number. name
is not a number, so isNaN(name)
returns true. age
is a number, so isNaN(age)
returns false
.
129. What's the output?
const randomValue = 21;
function getInfo() {
console.log(typeof randomValue);
const randomValue = 'Lydia Hallie';
}
getInfo();
- A:
"number"
- B:
"string"
- C:
undefined
- D:
ReferenceError
Answer
Answer: D
Variables declared with the const
keyword are not referencable before their initialization: this is called the temporal dead zone. In the getInfo
function, the variable randomValue
is scoped in the functional scope of getInfo
. On the line where we want to log the value of typeof randomValue
, the variable randomValue
isn't initialized yet: a ReferenceError
gets thrown! The engine didn't go down the scope chain since we declared the variable randomValue
in the getInfo
function.
130. What's the output?
const myPromise = Promise.resolve('Woah some cool data');
(async () => {
try {
console.log(await myPromise);
} catch {
throw new Error(`Oops didn't work`);
} finally {
console.log('Oh finally!');
}
})();
- A:
Woah some cool data
- B:
Oh finally!
- C:
Woah some cool data
Oh finally!
- D:
Oops didn't work
Oh finally!
Answer
Answer: C
In the try
block, we're logging the awaited value of the myPromise
variable: "Woah some cool data"
. Since no errors were thrown in the try
block, the code in the catch
block doesn't run. The code in the finally
block always runs, "Oh finally!"
gets logged.
131. What's the output?
const emojis = ['π₯', ['β¨', 'β¨', ['π', 'π']]];
console.log(emojis.flat(1));
- A:
['π₯', ['β¨', 'β¨', ['π', 'π']]]
- B:
['π₯', 'β¨', 'β¨', ['π', 'π']]
- C:
['π₯', ['β¨', 'β¨', 'π', 'π']]
- D:
['π₯', 'β¨', 'β¨', 'π', 'π']
Answer
Answer: B
With the flat
method, we can create a new, flattened array. The depth of the flattened array depends on the value that we pass. In this case, we passed the value 1
(which we didn't have to, that's the default value), meaning that only the arrays on the first depth will be concatenated. ['π₯']
and ['β¨', 'β¨', ['π', 'π']]
in this case. Concatenating these two arrays results in ['π₯', 'β¨', 'β¨', ['π', 'π']]
.
132. What's the output?
class Counter {
constructor() {
this.count = 0;
}
increment() {
this.count++;
}
}
const counterOne = new Counter();
counterOne.increment();
counterOne.increment();
const counterTwo = counterOne;
counterTwo.increment();
console.log(counterOne.count);
- A:
0
- B:
1
- C:
2
- D:
3
Answer
Answer: D
counterOne
is an instance of the Counter
class. The counter class contains a count
property on its constructor, and an increment
method. First, we invoked the increment
method twice by calling counterOne.increment()
. Currently, counterOne.count
is 2
.
Then, we create a new variable counterTwo
, and set it equal to counterOne
. Since objects interact by reference, we're just creating a new reference to the same spot in memory that counterOne
points to. Since it has the same spot in memory, any changes made to the object that counterTwo
has a reference to, also apply to counterOne
. Currently, counterTwo.count
is 2
.
We invoke the counterTwo.increment()
, which sets the count
to 3
. Then, we log the count on counterOne
, which logs 3
.
133. What's the output?
const myPromise = Promise.resolve(Promise.resolve('Promise!'));
function funcOne() {
myPromise.then(res => res).then(res => console.log(res));
setTimeout(() => console.log('Timeout!', 0));
console.log('Last line!');
}
async function funcTwo() {
const res = await myPromise;
console.log(await res);
setTimeout(() => console.log('Timeout!', 0));
console.log('Last line!');
}
funcOne();
funcTwo();
- A:
Promise! Last line! Promise! Last line! Last line! Promise!
- B:
Last line! Timeout! Promise! Last line! Timeout! Promise!
- C:
Promise! Last line! Last line! Promise! Timeout! Timeout!
- D:
Last line! Promise! Promise! Last line! Timeout! Timeout!
Answer
Answer: D
First, we invoke funcOne
. On the first line of funcOne
, we call the myPromise
promise, which is an asynchronous operation. While the engine is busy completing the promise, it keeps on running the function funcOne
. The next line is the asynchronous setTimeout
function, from which the callback is sent to the Web API. (see my article on the event loop here.)
Both the promise and the timeout are asynchronous operations, the function keeps on running while it's busy completing the promise and handling the setTimeout
callback. This means that Last line!
gets logged first, since this is not an asynchonous operation. This is the last line of funcOne
, the promise resolved, and Promise!
gets logged. However, since we're invoking funcTwo()
, the call stack isn't empty, and the callback of the setTimeout
function cannot get added to the callstack yet.
In funcTwo
we're, first awaiting the myPromise promise. With the await
keyword, we pause the execution of the function until the promise has resolved (or rejected). Then, we log the awaited value of res
(since the promise itself returns a promise). This logs Promise!
.
The next line is the asynchronous setTimeout
function, from which the callback is sent to the Web API.
We get to the last line of funcTwo
, which logs Last line!
to the console. Now, since funcTwo
popped off the call stack, the call stack is empty. The callbacks waiting in the queue (() => console.log("Timeout!")
from funcOne
, and () => console.log("Timeout!")
from funcTwo
) get added to the call stack one by one. The first callback logs Timeout!
, and gets popped off the stack. Then, the second callback logs Timeout!
, and gets popped off the stack. This logs Last line! Promise! Promise! Last line! Timeout! Timeout!
134. How can we invoke sum
in index.js
from sum.js?
// sum.js
export default function sum(x) {
return x + x;
}
// index.js
import * as sum from './sum';
- A:
sum(4)
- B:
sum.sum(4)
- C:
sum.default(4)
- D: Default aren't imported with
*
, only named exports
Answer
Answer: C
With the asterisk *
, we import all exported values from that file, both default and named. If we had the following file:
// info.js
export const name = 'Lydia';
export const age = 21;
export default 'I love JavaScript';
// index.js
import * as info from './info';
console.log(info);
The following would get logged:
{
default: "I love JavaScript",
name: "Lydia",
age: 21
}
For the sum
example, it means that the imported value sum
looks like this:
{ default: function sum(x) { return x + x } }
We can invoke this function, by calling sum.default
135. What's the output?
const handler = {
set: () => console.log('Added a new property!'),
get: () => console.log('Accessed a property!'),
};
const person = new Proxy({}, handler);
person.name = 'Lydia';
person.name;
- A:
Added a new property!
- B:
Accessed a property!
- C:
Added a new property!
Accessed a property!
- D: Nothing gets logged
Answer
Answer: C
With a Proxy object, we can add custom behavior to an object that we pass to it as the second argument. In tis case, we pass the handler
object which contained to properties: set
and get
. set
gets invoked whenever we set property values, get
gets invoked whenever we get (access) property values.
The first argument is an empty object {}
, which is the value of person
. To this object, the custom behavior specified in the handler
object gets added. If we add a property to the person
object, set
will get invoked. If we access a property on the person
object, get
gets invoked.
First, we added a new property name
to the proxy object (person.name = "Lydia"
). set
gets invoked, and logs "Added a new property!"
.
Then, we access a property value on the proxy object, the get
property on the handler object got invoked. "Accessed a property!"
gets logged.
136. Which of the following will modify the person
object?
const person = { name: 'Lydia Hallie' };
Object.seal(person);
- A:
person.name = "Evan Bacon"
- B:
person.age = 21
- C:
delete person.name
- D:
Object.assign(person, { age: 21 })
Answer
Answer: A
With Object.seal
we can prevent new properies from being added, or existing properties to be removed.
However, you can still modify the value of existing properties.
137. Which of the following will modify the person
object?
const person = {
name: 'Lydia Hallie',
address: {
street: '100 Main St',
},
};
Object.freeze(person);
- A:
person.name = "Evan Bacon"
- B:
delete person.address
- C:
person.address.street = "101 Main St"
- D:
person.pet = { name: "Mara" }
Answer
Answer: C
The Object.freeze
method freezes an object. No properties can be added, modified, or removed.
However, it only shallowly freezes the object, meaning that only direct properties on the object are frozen. If the property is another object, like address
in this case, the properties on that object aren't frozen, and can be modified.
138. What's the output?
const add = x => x + x;
function myFunc(num = 2, value = add(num)) {
console.log(num, value);
}
myFunc();
myFunc(3);
- A:
2
4
and3
6
- B:
2
NaN
and3
NaN
- C:
2
Error
and3
6
- D:
2
4
and3
Error
Answer
Answer: A
First, we invoked myFunc()
without passing any arguments. Since we didn't pass arguments, num
and value
got their default values: num is 2
, and value
the returned value of the function add
. To the add
function, we pass num
as an argument, which had the value of 2
. add
returns 4
, which is the value of value
.
Then, we invoked myFunc(3)
and passed the value 3
as the value for the argument num
. We didn't pass an argument for value
. Since we didn't pass a value for the value
argument, it got the default value: the returned value of the add
function. To add
, we pass num
, which has the value of 3
. add
returns 6
, which is the value of value
.
139. What's the output?
class Counter {
#number = 10
increment() {
this.#number++
}
getNum() {
return this.#number
}
}
const counter = new Counter()
counter.increment()
console.log(counter.#number)
- A:
10
- B:
11
- C:
undefined
- D:
SyntaxError
Answer
Answer: D
In ES2020, we can add private variables in classes by using the #
. We cannot access these variables outside of the class. When we try to log counter.#number
, a SyntaxError gets thrown: we cannot acccess it outside the Counter
class!
140. What's the missing?
const teams = [
{ name: 'Team 1', members: ['Paul', 'Lisa'] },
{ name: 'Team 2', members: ['Laura', 'Tim'] },
];
function* getMembers(members) {
for (let i = 0; i < members.length; i++) {
yield members[i];
}
}
function* getTeams(teams) {
for (let i = 0; i < teams.length; i++) {
// β¨ SOMETHING IS MISSING HERE β¨
}
}
const obj = getTeams(teams);
obj.next(); // { value: "Paul", done: false }
obj.next(); // { value: "Lisa", done: false }
- A:
yield getMembers(teams[i].members)
- B:
yield* getMembers(teams[i].members)
- C:
return getMembers(teams[i].members)
- D:
return yield getMembers(teams[i].members)
Answer
Answer: B
In order to iterate over the members
in each element in the teams
array, we need to pass teams[i].members
to the getMembers
generator function. The generator function returns a generator object. In order to iterate over each element in this generator object, we need to use yield*
.
If we would've written yield
, return yield
, or return
, the entire generator function would've gotten returned the first time we called the next
method.
141. What's the output?
const person = {
name: 'Lydia Hallie',
hobbies: ['coding'],
};
function addHobby(hobby, hobbies = person.hobbies) {
hobbies.push(hobby);
return hobbies;
}
addHobby('running', []);
addHobby('dancing');
addHobby('baking', person.hobbies);
console.log(person.hobbies);
- A:
["coding"]
- B:
["coding", "dancing"]
- C:
["coding", "dancing", "baking"]
- D:
["coding", "running", "dancing", "baking"]
Answer
Answer: C
The addHobby
function receives two arguments, hobby
and hobbies
with the default value of the hobbies
array on the person
object.
First, we invoke the addHobby
function, and pass "running"
as the value for hobby
and an empty array as the value for hobbies
. Since we pass an empty array as the value for y
, "running"
gets added to this empty array.
Then, we invoke the addHobby
function, and pass "dancing"
as the value for hobby
. We didn't pass a value for hobbies
, so it gets the default value, the hobbies
property on the person
object. We push the hobby dancing
to the person.hobbies
array.
Last, we invoke the addHobby
function, and pass "bdaking"
as the value for hobby
, and the person.hobbies
array as the value for hobbies
. We push the hobby baking
to the person.hobbies
array.
After pushing dancing
and baking
, the value of person.hobbies
is ["coding", "dancing", "baking"]
142. What's the output?
class Bird {
constructor() {
console.log("I'm a bird. π¦’");
}
}
class Flamingo extends Bird {
constructor() {
console.log("I'm pink. πΈ");
super();
}
}
const pet = new Flamingo();
- A:
I'm pink. πΈ
- B:
I'm pink. πΈ
I'm a bird. π¦’
- C:
I'm a bird. π¦’
I'm pink. πΈ
- D: Nothing, we didn't call any method
Answer
Answer: B
We create the variable pet
which is an instance of the Flamingo
class. When we instantiate this instance, the constructor
on Flamingo
gets called. First, "I'm pink. πΈ"
gets logged, after which we call super()
. super()
calls the constructor of the parent class, Bird
. THe constructor in Bird
gets called, and logs "I'm a bird. π¦’"
.
143. Which of the options result(s) in an error?
const emojis = ['π', 'π
πΌ', 'π', 'β'];
/* 1 */ emojis.push('π¦');
/* 2 */ emojis.splice(0, 2);
/* 3 */ emojis = [...emojis, 'π₯'];
/* 4 */ emojis.length = 0;
- A: 1
- B: 1 and 2
- C: 3 and 4
- D: 3
Answer
Answer: D
The const
keyword simply means we cannot redeclare the value of that variable, it's read-only. However, the value itself isn't immutable. The propeties on the emojis
array can be modified, for example by pushing new values, splicing them, or setting the length of the array to 0.
144. What do we need to add to the person
object to get ["Lydia Hallie", 21]
as the output of [...person]
?
const person = {
name: "Lydia Hallie",
age: 21
}
[...person] // ["Lydia Hallie", 21]
- A: Nothing, object are iterable by default
- B:
*[Symbol.iterator]() { for (let x in this) yield* this[x] }
- C:
*[Symbol.iterator]() { yield* Object.values(this) }
- D:
*[Symbol.iterator]() { for (let x in this) yield this }
Answer
Answer: C
Objects aren't iterable by default. An iterable is an iterable if the iterator protocol is present. We can add this manually by adding the iterator symbol [Symbol.iterator]
, which has to return a generator object, for example by making it a generator function *[Symbol.iterator]() {}
. This generator function has to yield the Object.values
of the person
object if we want it to return the array ["Lydia Hallie", 21]
: yield* Object.values(this)
.
146. What's the output?
let count = 0;
const nums = [0, 1, 2, 3];
nums.forEach(num => {
if (num) count += 1
})
console.log(count)
- A: 1
- B: 2
- C: 3
- D: 4
Answer
Answer: C
The if
condition within the forEach
loop checks whether the value of num
is truthy or falsy. Since the first number in the nums
array is 0
, a falsy value, the if
statement's code block won't be executed. count
only gets incremented for the other 3 numbers in the nums
array, 1
, 2
and 3
. Since count
gets incremented by 1
3 times, the value of count
is 3
.
147. What's the output?
function getFruit(fruits) {
console.log(fruits?.[1]?.[1])
}
getFruit([['π', 'π'], ['π']])
getFruit()
getFruit([['π'], ['π', 'π']])
- A:
null
,undefined
, π - B:
[]
,null
, π - C:
[]
,[]
, π - D:
undefined
,undefined
, π
Answer
Answer: D
The ?
allows us to optionally access deeper nested properties within objects. We're trying to log the item on index 1
within the subarray that's on index 1
of the fruits
array. If the subarray on index 1
in the fruits
array doesn't exist, it'll simply return undefined
. If the subarray on index 1
in the fruits
array exists, but this subarray doesn't have an item on its 1
index, it'll also return undefined
.
First, we're trying to log the second item in the ['π']
subarray of [['π', 'π'], ['π']]]
. This subarray only contains one item, which means there is no item on index 1
, and returns undefined
.
Then, we're invoking the getFruits
function without passing a value as an argument, which means that fruits
has a value of undefined
by default. Since we're conditionally chaining the item on index 1
offruits
, it returns undefined
since this item on index 1
does not exist.
Lastly, we're trying to log the second item in the ['π', 'π']
subarray of ['π'], ['π', 'π']
. The item on index 1
within this subarray is π
, which gets logged.
148. What's the output?
class Calc {
constructor() {
this.count = 0
}
increase() {
this.count ++
}
}
const calc = new Calc()
new Calc().increase()
console.log(calc.count)
- A:
0
- B:
1
- C:
undefined
- D:
ReferenceError
Answer
Answer: A
We set the variable calc
equal to a new instance of the Calc
class. Then, we instantiate a new instance of Calc
, and invoke the increase
method on this instance. Since the count property is within the constructor of the Calc
class, the count property is not shared on the prototype of Calc
. This means that the value of count has not been updated for the instance calc points to, count is still 0
.
149. What's the output?
const user = {
email: "e@mail.com",
password: "12345"
}
const updateUser = ({ email, password }) => {
if (email) {
Object.assign(user, { email })
}
if (password) {
user.password = password
}
return user
}
const updatedUser = updateUser({ email: "new@email.com" })
console.log(updatedUser === user)
- A:
false
- B:
true
- C:
TypeError
- D:
ReferenceError
Answer
Answer: B
The updateUser
function updates the values of the email
and password
properties on user, if their values are passed to the function, after which the function returns the user
object. The returned value of the updateUser
function is the user
object, which means that the value of updatedUser is a reference to the same user
object that user
points to. updatedUser === user
equals true
.
150. What's the output?
const fruit = ['π', 'π', 'π']
fruit.slice(0, 1)
fruit.splice(0, 1)
fruit.unshift('π')
- A:
['π', 'π', 'π']
- B:
['π', 'π']
- C:
['π', 'π', 'π']
- D:
['π', 'π', 'π', 'π']
Answer
Answer: C
First, we invoke the slice
method on the fruit array. The slice method does not modify the original array, but returns the value that it sliced off the array: the banana emoji.
Then, we invoke the splice
method on the fruit array. The splice method does modify the original array, which means that the fruit array now consists of ['π', 'π']
.
At last, we invoke the unshift
method on the fruit
array, which modifies the original array by adding the provided value, βπβ in this case, as the first element in the array. The fruit array now consists of ['π', 'π', 'π']
.
151. What's the output?
const animals = {};
let dog = { emoji: 'πΆ' }
let cat = { emoji: 'π' }
animals[dog] = { ...dog, name: "Mara" }
animals[cat] = { ...cat, name: "Sara" }
console.log(animals[dog])
- A:
{ emoji: "πΆ", name: "Mara" }
- B:
{ emoji: "π", name: "Sara" }
- C:
undefined
- D:
ReferenceError
Answer
Answer: B
Object keys are converted to strings.
Since the value of dog
is an object, animals[dog]
actually means that weβre creating a new property called "object Object"
equal to the new object. animals["object Object"]
is now equal to { emoji: "πΆ", name: "Mara"}
.
cat
is also an object, which means that animals[cat]
actually means that weβre overwriting the value of animals[``"``object Object``"``]
with the new cat properties.
Logging animals[dog]
, or actually animals["object Object"]
since converting the dog
object to a string results "object Object"
, returns the { emoji: "π", name: "Sara" }
.
152. What's the output?
const user = {
email: "my@email.com",
updateEmail: email => {
this.email = email
}
}
user.updateEmail("new@email.com")
console.log(user.email)
- A:
my@email.com
- B:
new@email.com
- C:
undefined
- D:
ReferenceError
Answer
Answer: A
The updateEmail
function is an arrow function, and is not bound to the user
object. This means that the this
keyword is not referring to the user
object, but refers to the global scope in this case. The value of email
within the user
object does not get updated. When logging the value of user.email
, the original value of my@email.com
gets returned.
153. What's the output?
const promise1 = Promise.resolve('First')
const promise2 = Promise.resolve('Second')
const promise3 = Promise.reject('Third')
const promise4 = Promise.resolve('Fourth')
const runPromises = async () => {
const res1 = await Promise.all([promise1, promise2])
const res2 = await Promise.all([promise3, promise4])
return [res1, res2]
}
runPromises()
.then(res => console.log(res))
.catch(err => console.log(err))
- A:
[['First', 'Second'], ['Fourth']]
- B:
[['First', 'Second'], ['Third', 'Fourth']]
- C:
[['First', 'Second']]
- D:
'Third'
Answer
Answer: D
The Promise.all
method runs the passed promises in parallel. If one promise fails, the Promise.all
method _rejects) with the value of the rejected promise. In this case, promise3
rejected with the value "Third"
. Weβre catching the rejected value in the chained catch
method on the runPromises
invocation to catch any errors within the runPromises
function. Only "Third"
gets logged, since promise3
rejected with this value.
154. What should the value of method
be to log { name: "Lydia", age: 22 }
?
const keys = ["name", "age"]
const values = ["Lydia", 22]
const method = /* ?? */
Object[method](keys.map((_, i) => {
return [keys[i], values[i]]
})) // { name: "Lydia", age: 22 }
- A:
entries
- B:
values
- C:
fromEntries
- D:
forEach
Answer
Answer: C
The fromEntries
method turns a 2d array into an object. The first element in each subarray will be the key, and the second element in each subarray will be the value. In this case, weβre mapping over the keys
array, which returns an array which first element is the item on the key array on the current index, and the second element is the item of the values array on the current index.
This creates an array of subarrays containing the correct keys and values, which results in { name: "Lydia", age: 22 }
155. What's the output?
const createMember = ({ email, address = {}}) => {
const validEmail = /.+\@.+\..+/.test(email)
if (!validEmail) throw new Error("Valid email pls")
return {
email,
address: address ? address : null
}
}
const member = createMember({ email: "my@email.com" })
console.log(member)
- A:
{ email: "my@email.com", address: null }
- B:
{ email: "my@email.com" }
- C:
{ email: "my@email.com", address: {} }
- D:
{ email: "my@email.com", address: undefined }
Answer
Answer: C
The default value of address
is an empty object {}
. When we set the variable member
equal to the object returned by the createMember
function, we didn't pass a value for address, which means that the value of address is the default empty object {}
. An empty object is a truthy value, which means that the condition of the address ? address : null
conditional returns true
. The value of address is the empty object {}
.
156. What's the output?
let randomValue = { name: "Lydia" }
randomValue = 23
if (!typeof randomValue === "string") {
console.log("It's not a string!")
} else {
console.log("Yay it's a string!")
}
- A:
It's not a string!
- B:
Yay it's a string!
- C:
TypeError
- D:
undefined
Answer
Answer: B
The condition within the if
statement checks whether the value of !typeof randomValue
is equal to "string"
. The !
operator converts the value to a boolean value. If the value is truthy, the returned value will be false
, if the value is falsy, the returned value will be true
. In this case, the returned value of typeof randomValue
is the truthy value "string"
, meaning that the value of !typeof randomValue
is the boolean value false
.
!typeof randomValue === "string"
always returns false, since we're actually checking false === "string"
. Since the condition returned false
, the code block of the else
statement gets run, and Yay it's a string!
gets logged.